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MySQL Query — get specific parts of a string that is in many rows
I have a table with 1 column that contains
txt1
ttt1
zxcz
zzct
ttct
zzzx
tttt
I need a query that will return the following two rows
txt1
zzzx
I was trying to do this using FIND_IN_SET, but this only works with a number of arguments and I need something that works with a string.
My latest attempt:
SELECT * FROM table WHERE text = ‘txt1’ AND FIND_IN_SET(word, `text`) > 0
I need to do this with any row that has the same word in the text column, the only thing that’s different between those rows is the string in the brackets surrounding it.
EDIT:
I should have mentioned this earlier but, this table is stored in a database, the reason I used the same word is because one of the values is a login that has a password in the brackets.
A:
Assuming that the pattern for the word in the parentheses is always «txt» or «zz», and the word to be matched is always preceded by a txt and followed by zz, the pattern you’re looking for is /txt1(.*)zz/ (note that the closing ) is optional)
You can then use LIKE, eg:
select *
from mytable
where text like ‘%txt1%’
or text like ‘%txt1(.*)zz%’
Since your pattern is rather complex, you’ll probably want to use the REGEXP operator instead of LIKE, eg:
select *
from mytable
where text REGEXP ‘^txt1(.*)zz$’
Note that this probably isn’t the most efficient way to implement your query, since you’re searching for a pattern that may occur anywhere in your text.
Fiddle here:
Q:
How to handle
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